(5x+1)(2x^2+4x-1)=

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Solution for (5x+1)(2x^2+4x-1)= equation:


Simplifying
(5x + 1)(2x2 + 4x + -1) = 0

Reorder the terms:
(1 + 5x)(2x2 + 4x + -1) = 0

Reorder the terms:
(1 + 5x)(-1 + 4x + 2x2) = 0

Multiply (1 + 5x) * (-1 + 4x + 2x2)
(1(-1 + 4x + 2x2) + 5x * (-1 + 4x + 2x2)) = 0
((-1 * 1 + 4x * 1 + 2x2 * 1) + 5x * (-1 + 4x + 2x2)) = 0
((-1 + 4x + 2x2) + 5x * (-1 + 4x + 2x2)) = 0
(-1 + 4x + 2x2 + (-1 * 5x + 4x * 5x + 2x2 * 5x)) = 0
(-1 + 4x + 2x2 + (-5x + 20x2 + 10x3)) = 0

Reorder the terms:
(-1 + 4x + -5x + 2x2 + 20x2 + 10x3) = 0

Combine like terms: 4x + -5x = -1x
(-1 + -1x + 2x2 + 20x2 + 10x3) = 0

Combine like terms: 2x2 + 20x2 = 22x2
(-1 + -1x + 22x2 + 10x3) = 0

Solving
-1 + -1x + 22x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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